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Plant electrical calculators

Single- and three-phase power, motors, power factor, voltage drop, transformers and batteries: 14 everyday plant calculations.

Basics and energy

Ohm's law and DC power

FormulaR = U ÷ I  ·  P = U × I = U² ÷ R = R × I²
V
A
Resistance (R)—Ω
Power (P)—W

Also valid in AC for a purely resistive load. A resistor that dissipates more than its rating overheats and burns. Electrical work: qualified person and lockout only.

Resistors in series and parallel

FormulaRs = R₁ + R₂ + R₃  ·  1 ÷ Rp = 1 ÷ R₁ + 1 ÷ R₂ + 1 ÷ R₃
Ω
Ω
Ω
Series equivalent (Rs)—Ω
Parallel equivalent (Rp)—Ω

In parallel, the equivalent is always smaller than the smallest resistor. Measure resistance de-energised, with the circuit isolated. Electrical work: qualified person and lockout only.

Heating element: resistance and current

FormulaR = Un² ÷ Pn  ·  I = U ÷ R  ·  P = U² ÷ R
kW
V
V
Element resistance (R)—Ω
Current at rated voltage—A
Power at actual voltage—kW
Current at actual voltage—A

Per element, resistance assumed constant (it changes a little with temperature). A 240 V element on 208 V loses about 25 % of its power. Electrical work: qualified person and lockout only.

Energy used (kWh)

FormulaE = P × α ÷ 100 × h × n
kW
%
h/d
d/yr
Average power drawn—kW
Energy per day—kWh/d
Energy per year—kWh/yr

Load factor = average power actually drawn ÷ connected power. For a motor, measure the input power rather than trusting the nameplate.

Battery / UPS runtime

FormulaE = C × U × DoD ÷ 100  ·  t = E × η ÷ 100 ÷ P
Ah
V
W
%
%
Usable battery energy—Wh
Estimated runtime—h
Estimated runtime—min

Estimate only: real capacity drops at high discharge current (Peukert effect), in the cold and with age. Allow a 20 to 25 % margin and run a discharge test. Electrical work: qualified person and lockout only.

AC power and distribution

Single-phase power

FormulaS = U × I ÷ 1000  ·  P = S × cos φ  ·  Q = S × sin φ
V
A
Apparent power (S)—kVA
Active power (P)—kW
Reactive power (Q)—kvar

Measure the power factor with a power analyser; otherwise use the nameplate value (valid at full load only). Electrical work: qualified person and lockout only.

Three-phase power

FormulaS = √3 × U × I ÷ 1000  ·  P = S × cos φ  ·  Q = S × sin φ
V
A
Apparent power (S)—kVA
Active power (P)—kW
Reactive power (Q)—kvar

U = line-to-line voltage, I = line current (average of the three phases). Balanced load assumed; if the currents differ by more than 10 %, find out why. Electrical work: qualified person and lockout only.

Power factor correction (capacitors)

FormulaQc = P × (tan φ₁ − tan φ₂)  ·  S = P ÷ cos φ
kW
Capacitors required (Qc)—kvar
Apparent power before—kVA
Apparent power after—kVA
Drop in line current—%

Do not aim above 0.95 to 0.98: overcompensation at light load and a resonance risk with drive harmonics. Capacitors stay charged after switch-off: wait for discharge and verify absence of voltage. Electrical work: qualified person and lockout only.

Transformer: full-load and short-circuit current

FormulaIn = S × 1000 ÷ (k × U)  (k = √3 : 3φ, 1 : 1φ)  ·  Isc = In × 100 ÷ Z%
kVA
V
%
Secondary full-load current (In)—A
Maximum short-circuit current (Isc)—kA

Short circuit at the secondary terminals with an infinite upstream source: a conservative value to check breaking capacity. Arc-flash and coordination studies need a full calculation. Electrical work: qualified person and lockout only.

Cable voltage drop

FormulaΔU = b × L × I × (ρ ÷ S × cos φ + λ × sin φ)  (b = √3 : 3φ, 2 : 1φ)  ·  ΔU% = ΔU ÷ U × 100
V
A
m
mm²
Voltage drop (ΔU)—V
Voltage drop (ΔU%)—%
Voltage at the load—V

IEC 60364-5-52 Annex G method: ρ in service 0.0225 (copper) or 0.036 (aluminium) Ω·mm²/m, λ = 0.08 mΩ/m. Usual guide: 3 to 5 % in total; the local electrical code governs. Electrical work: qualified person and lockout only.

Motors and drives

Motor full-load current

FormulaP₁ = P ÷ η  ·  In = P₁ × 1000 ÷ (k × U × cos φ)  (k = √3 : 3φ, 1 : 1φ)
kW
V
%
Input power (P₁)—kW
Full-load current (In)—A

P = mechanical shaft power (nameplate). Estimate only: set overload protection from the nameplate current and size conductors from the electrical code tables. Electrical work: qualified person and lockout only.

Synchronous speed and slip

FormulaNs = 120 × f ÷ p  ·  s = (Ns − N) ÷ Ns × 100
Hz
rpm
Synchronous speed (Ns)—rpm
Slip (s)—%

p = number of poles (2 × pole pairs). Typical full-load slip of an induction motor: 1 to 5 %; it rises with load, so speed tells you about load.

Motor starting current

FormulaId = In × k  ·  IY-Δ = Id ÷ 3
A
×
Direct-on-line start—A
Star-delta start—A

k comes from the nameplate or motor data sheet (often 5 to 8). With star-delta, starting torque also drops to one third. Starting current lasts a few seconds. Electrical work: qualified person and lockout only.

Variable speed drive: reduced power (affinity laws)

FormulaP₂ = P₁ × (N₂ ÷ N₁)³  ·  E = (P₁ − P₂) × h
kW
%
h/yr
Power at the new speed (P₂)—kW
Power saved—kW
Energy saved per year—kWh/yr

Ideal cube law: centrifugal pump or fan with no static head. With static head and drive (2 to 4 %) and motor losses, real savings are lower: measure them.

Learning and checking tools. The ranges shown are general guidance: always follow your plant's procedures, permits and set points. Nothing is sent anywhere: the calculations run in your browser.